Question

Диме имаме вместе 40 лет,Диме и папе-42 года,а Диме,маме и папе вместе 74 года.Сколько лет каждому?

Answer 1

Диме,маме и папе вместе 74 года,а Диме и маме вместе 40 лет.Подставляем

40+папа=74года

папа=74-40=34года папе.

 Диме и папе=42 года,отсюда

Дима+34 =42

Дима=42-34=8лет Диме.

Тогда маме

8+мама=40

мама=40-8=32 года.

Ответ: Диме 8лет;папе-34 года;маме-32года. 

Answer 2

Problem Analysis

We are given the following information: - The sum of Dima's age and his mother's age is 40 years. - The sum of Dima's age and his father's age is 42 years. - The sum of Dima's age, his mother's age, and his father's age is 74 years.

We need to determine the age of each person.

Solution

Let's assign variables to represent the ages of Dima, his mother, and his father. We'll use the following variables: - Dima's age: D - Dima's mother's age: M - Dima's father's age: F

From the given information, we can write the following equations:

1. D + M = 40 (Equation 1) 2. D + F = 42 (Equation 2) 3. D + M + F = 74 (Equation 3)

To solve this system of equations, we can use substitution or elimination. Let's use the substitution method.

From Equation 1, we can express M in terms of D: M = 40 - D

Substituting this value of M into Equation 3, we get: D + (40 - D) + F = 74 Simplifying, we have: 40 + F = 74 F = 74 - 40 F = 34

Now, substituting the value of F into Equation 2, we get: D + 34 = 42 D = 42 - 34 D = 8

Finally, substituting the values of D and F into Equation 1, we get: 8 + M = 40 M = 40 - 8 M = 32

Therefore, Dima is 8 years old, his mother is 32 years old, and his father is 34 years old.

Answer

Dima is 8 years old, his mother is 32 years old, and his father is 34 years old.