Question

Из 1 города одновременно в противоположных направлениях выехали 2 мотоциклиста, и через 1,2 часа окозались на расстояние 156 км друг от друга. Найдите скорость каждого, если скорость 1 из них в 1,6 < скорости другого

Answer 1

Х - скорость одного мотоциклиста
1,6х - скорость другого мотоциклиста , из условия задачи имем
(х +1,6х)*1,2 =156       3,12х = 156        х = 50 км/ч -скорость одного мотоциклиста
1,6х = 1,6 * 50 = 80 км/ч - скорость другого мотоциклиста 

Answer 2

Problem Analysis

We have two motorcyclists who start simultaneously from the same city in opposite directions. After 1.2 hours, they are 156 km apart. We need to find the speed of each motorcyclist, given that the speed of one of them is 1.6 times the speed of the other.

Solution

Let's assume the speed of one motorcyclist is x km/h. Then the speed of the other motorcyclist would be 1.6x km/h, as given in the problem.

We can use the formula distance = speed × time to solve this problem.

After 1.2 hours, the distance covered by the first motorcyclist would be 1.2x km, and the distance covered by the second motorcyclist would be 1.2 × 1.6x km.

According to the problem, the total distance covered by both motorcyclists is 156 km. So we can write the equation:

1.2x + 1.2 × 1.6x = 156

Simplifying the equation:

1.2x + 1.92x = 156

3.12x = 156

Dividing both sides of the equation by 3.12:

x = 156 / 3.12

x = 50

So the speed of the first motorcyclist is 50 km/h and the speed of the second motorcyclist is 1.6 × 50 = 80 km/h.

Therefore, the speed of the first motorcyclist is 50 km/h and the speed of the second motorcyclist is 80 km/h.