Question

Два поезда вышли в разное время навстречу друг другу из двух городов,расстояние между которыми 782км.Скорость первого поезда-52 км/ч,а скорость второго 61 км/ч. Пройдя 416 км первый поезд встретился со вторым.На сколько один из поездов вышел раньше другого?

Answer 1

416/52=8 часов ехал первый до встречи
782-416=366км проехал второй
366/61=6 часов ехал второй
первый вышел раньше на два часа

Answer 2

Problem Analysis

We have two trains traveling towards each other from two different cities. The distance between the cities is 782 km. The first train has a speed of 52 km/h, and the second train has a speed of 61 km/h. The first train meets the second train after traveling 416 km. We need to determine how much earlier one train left compared to the other.

Solution

To solve this problem, we can use the formula:

Time = Distance / Speed

Let's calculate the time it takes for each train to travel the given distances.

The time taken by the first train to travel 416 km is: Time taken by first train = 416 km / 52 km/h

The time taken by the second train to travel the remaining distance (782 km - 416 km = 366 km) is: Time taken by second train = 366 km / 61 km/h

Now, we can compare the times taken by the two trains to determine which train left earlier.

Calculation

Let's calculate the time taken by each train and determine which train left earlier.

Time taken by the first train: Time taken by first train = 416 km / 52 km/h = 8 hours

Time taken by the second train: Time taken by second train = 366 km / 61 km/h ≈ 6 hours

Since the second train took less time to cover the remaining distance, it means the second train left earlier than the first train.

Answer

The second train left earlier than the first train.

Please let me know if I can help you with anything else.