Question

Решите 2 задание......

Answer 1

$S(t)=3t^2-cos(2t)-10\\S'(t)=V(t)\\S''(t)=a(t)\\\\S'(t)=6t+2sin(2t)\\V(15)=6*15+2*sin(30)\\V(15)=81\\S''(t)=6+4cos(2t)\\a(15)=6+4cos(30)\\a(15)=6+2 \sqrt{3}=9,46$