Question

(2x+4y)во второй степени. 1дробь2x+)во второй степени(0,3x+1)^2(5+4x)^2(x+1дробь 10)^2

Answer 1

${(2x + 4y)}^{2} = 4 {x}^{2} + 16 {y}^{2} + 16xy$
${(0.3x + 1)}^{2} = 0.09 {x}^{2} + 1 + 0.6x$
${(5 + 4x)}^{2} = 25 + 16 {x}^{2} + 40x$
${(x + \frac{1}{10} )}^{2} = {(x + 0.1)}^{2} = {x}^{2} + 0.01 + 0.2x$