Question

Из двух деревень,расстояние между которым 27 км,одновременно навстречу друг другу вышли две группы туристов.Через 3 ч они встретились. Какова была скорость первой групы туристов , если скорость второй групы 5 км?

Answer 1

1)27:3=9
2)9-5=4км/в час со скоростью группы туристов

Answer 2

1)27:3=9 км                                                                                                                                      2) 9-5=4 км/час скорость 1 группы туристов

Answer 3

This is a problem of uniform motion. To solve it, we need to use the formula:

$$S = v \times t$$

where $S$ is the distance, $v$ is the speed, and $t$ is the time.

Let $v_1$ be the speed of the first group of tourists, and $v_2$ be the speed of the second group. We know that $v_2 = 5$ km/h. We also know that the distance between the two villages is $S = 27$ km, and the time of meeting is $t = 3$ hours.

We can write two equations for the distances traveled by each group before meeting:

$$S_1 = v_1 \times t$$ $$S_2 = v_2 \times t$$

Since the sum of the distances is equal to the total distance, we can write:

$$S_1 + S_2 = S$$

Substituting the values of $S$, $t$, and $v_2$, we get:

$$v_1 \times 3 + 5 \times 3 = 27$$

Solving for $v_1$, we get:

$$v_1 = \frac{27 - 15}{3} = 4$$

Therefore, the speed of the first group of tourists is 4 km/h.