Question

Начерти прямоугольник ,периметр которого равен 210мм., а длина одной стороны составляет одну шестую часть длины другой стороны . вычесли площадь этого прямоугольника.без икса(х) решите ПОМОГИТЕ ПОЖАЛУЙСТА!!!!

Answer 1

то есть 

2(a+b)=210

a+b=105

a+1/6a=105

6a+a=105

7a=105

a= 15

6a=6*15=90

то есть  

Площадь равна S=15*90   =1350мм  квадрат

Answer 2

Problem Analysis

We are given that the perimeter of a rectangle is 210 mm, and the length of one side is one-sixth the length of the other side. We need to find the area of this rectangle.

Solution

Let's assume the length of one side of the rectangle is x mm. According to the given information, the length of the other side will be 6x mm.

The perimeter of a rectangle is given by the formula: 2(length + width). In this case, the perimeter is 210 mm, so we can write the equation as:

2(x + 6x) = 210

Simplifying the equation, we get:

2(7x) = 210

14x = 210

Dividing both sides of the equation by 14, we find:

x = 15

Therefore, the length of one side of the rectangle is 15 mm, and the length of the other side is 6 times that, which is 90 mm.

To find the area of the rectangle, we use the formula: Area = length * width. Substituting the values, we get:

Area = 15 * 90 = 1350 mm^2

So, the area of the rectangle is 1350 mm^2.

I hope this helps! Let me know if you have any further questions.