Question

Решите задачу! 5 насосов за 3 ч. откачали 1800 м(3) воды. Найдите объем воды, которую могут откачать 4 таких же насоса за 4 ч.

Answer 1

1) 1800 : 3 = 600 куб.м -откачивает 5 насосов за 1 час
2) 600 : 5 = 120 куб.м.- откачивает 1 насос за 1 час
3) 120 *4 = 480 куб.м. -откачают 4 насоса за 1 час
4) 480 * 4 = 1920 куб.м. -откачают 4 насоса за 4 часа
Ответ: 1920 куб.м. 

Answer 2

Problem Analysis

We are given that 5 pumps can pump 1800 m^3 of water in 3 hours. We need to find the volume of water that 4 pumps can pump in 4 hours.

Solution

To solve this problem, we can use the concept of pump efficiency. The efficiency of a pump is defined as the volume of water it can pump in a given time. Let's assume the efficiency of each pump is E m^3/hour.

We are given that 5 pumps can pump 1800 m^3 of water in 3 hours. Therefore, the total efficiency of the 5 pumps is 1800 m^3 / 3 hours = 600 m^3/hour.

Since we have 4 pumps now, the total efficiency of the 4 pumps will be 600 m^3/hour divided by 5 pumps multiplied by 4 pumps, which is (600 m^3/hour / 5 pumps) * 4 pumps = 480 m^3/hour.

Now, we need to find the volume of water that 4 pumps can pump in 4 hours. We can calculate this by multiplying the efficiency of the 4 pumps by the time of 4 hours:

Volume of water = Efficiency of 4 pumps * Time = 480 m^3/hour * 4 hours = 1920 m^3

Therefore, 4 pumps can pump 1920 m^3 of water in 4 hours.

Answer: The volume of water that 4 pumps can pump in 4 hours is 1920 m^3.