Question

А) Продавец фасовал сахарный песок, насывпая его в пакеты. Он добавил 100г - оказалось больше, чем 2 кг; убрал 60г - оказалась меньше, 2 кг; добавил 15 г и получил ровно 2 кг. Сколько граммов сахара насыпал продавец в пакет первоначально?

Answer 1

X-первоначально      2кг=2000г
x+15=2000
x=200-15=1985г

Answer 2

Problem Analysis

The problem states that a seller was packaging sugar into bags. Initially, the seller added 100g of sugar, which turned out to be more than 2kg. Then, the seller removed 60g of sugar, and it turned out to be less than 2kg. Finally, the seller added 15g of sugar and ended up with exactly 2kg. We need to determine how many grams of sugar the seller initially put in the bag.

Solution

Let's assume that the initial amount of sugar the seller put in the bag is represented by the variable x (in grams).

According to the problem, the following conditions are given: 1. Adding 100g of sugar resulted in more than 2kg. 2. Removing 60g of sugar resulted in less than 2kg. 3. Adding 15g of sugar resulted in exactly 2kg.

We can set up the following equations based on these conditions:

1. Adding 100g of sugar resulted in more than 2kg: - x + 100 > 2000 (since 2kg is equal to 2000g)

2. Removing 60g of sugar resulted in less than 2kg: - x - 60 < 2000

3. Adding 15g of sugar resulted in exactly 2kg: - x + 15 = 2000

To find the value of x, we can solve these equations simultaneously.

Solving the Equations

Let's solve the equations to find the value of x.

From equation 3, we have: x + 15 = 2000 Simplifying, we get: x = 2000 - 15 x = 1985

Therefore, the seller initially put 1985 grams of sugar in the bag.

Answer

The seller initially put 1985 grams of sugar in the bag.

Note: The solution provided above is based on the information given in the problem statement.