Question

Три прохода заходят в порт после каждого рейса первый пороход совершает свой рейс за 6дней второй за 5 дней 3 за 10 дней через сколько дней после выхода в рейс встретятся в порту все три порохода если все они вышли из порта аднавремменно

Answer 1

("Одновременно" пишется)
Нужно найти наименьшее общее кратное чисел
5, 3, 10

это число 30 
Ответ через 30 дней

Answer 2

Problem Analysis

We have three ships that enter a port after each of their respective voyages. The first ship takes 6 days for its voyage, the second ship takes 5 days, and the third ship takes 10 days. We need to determine how many days it will take for all three ships to meet in the port if they all left the port simultaneously.

Solution

To find the number of days it will take for all three ships to meet in the port, we need to find the least common multiple (LCM) of the three voyage durations.

The LCM of 6, 5, and 10 can be calculated as follows:

1. Find the prime factorization of each number: - 6 = 2 * 3 - 5 = 5 - 10 = 2 * 5

2. Take the highest power of each prime factor: - 2^1 * 3^1 * 5^1 = 2 * 3 * 5 = 30

Therefore, the LCM of 6, 5, and 10 is 30. It will take 30 days for all three ships to meet in the port if they all left the port simultaneously.

Answer

It will take 30 days for all three ships to meet in the port if they all left the port simultaneously.