Question

ДВА МАСТЕРА ДЕЛАЮТ ИГРУШКИ С ОДИНАКОВОЙ ПРОИЗВОДИТЕЛЬНОСТЬЮ. СНАЧАЛО ПЕРВЫЙ МАСТЕР СДЕЛАЛ 32 ИГРУШКИ, А ЗАТЕМ 2ОЙ МАСТЕР 24 ИГРУШКИ.ОБЩЕЕ ВРЕМЯ РАБОТЫ ДВУХ МАСТЕРОВ -14 ЧАСОВ. СКОЛЬКО ВРЕМЯ ЗАТРАТИЛ НА ЭТУ РАБОТУ КАЖДЫЙ МАСТЕР?

Answer 1

32+24=56 (игрушек всего)
56:14=4 (игрушки в час)
32:4=8 (час) первый мастер
24:4=6 (час) второй мастер
Ответ: первый мастер затратил на работу 8 часов, а второй 6 часов

Answer 2

Problem Analysis

We are given that two masters are making toys with the same productivity. The first master made 32 toys, and then the second master made 24 toys. The total time spent by both masters is 14 hours. We need to determine how much time each master spent on this work.

Solution

Let's assume that the time taken by the first master to make one toy is x hours. Therefore, the time taken by the second master to make one toy is also x hours.

We can set up the following equation based on the given information:

32x + 24x = 14

Simplifying the equation:

56x = 14

Dividing both sides by 56:

x = 14/56 = 0.25

Therefore, each master takes 0.25 hours (or 15 minutes) to make one toy.

Answer

Each master spent 0.25 hours (or 15 minutes) on this work.

Note: The sources provided do not contain relevant information for this specific problem.