Question

От двух станций расстояние между которыми равно 32км одновременно в одном направлении отошли два поезда. Сзади шёл поезд со скоростью 62км/ч, который через 4ч после начала движения догнал поезд, шедший в переди. Найдите скорость поезда шедшего в переди

Answer 1

V=S:t
32 км:4 ч=8 км/ч (на столько скорость 2-го поезда больше скорости 1-го)
62 км/ч-8 км/ч=54 км/ч
Ответ: скорость первого поезда 54 км/ч

Answer 2

Problem Analysis

We are given that the distance between two stations is 32 km. Two trains start simultaneously from these stations in the same direction. One train is traveling at a speed of 62 km/h, and it catches up to the other train after 4 hours. We need to find the speed of the train that was ahead.

Solution

Let's assume the speed of the train that was ahead is x km/h.

We know that the train behind is traveling at a speed of 62 km/h and catches up to the other train after 4 hours. This means that in 4 hours, the train behind has covered a distance of 62 km/h * 4 h = 248 km.

The total distance between the two stations is 32 km. Since the train behind catches up to the other train, the distance covered by the train ahead plus the distance covered by the train behind should be equal to the total distance between the stations.

Therefore, we can set up the following equation:

Distance covered by the train ahead + Distance covered by the train behind = Total distance between the stations

x km/h * 4 h + 248 km = 32 km

Simplifying the equation:

4x + 248 = 32

4x = 32 - 248

4x = -216

x = -216 / 4

x = -54

The speed of the train that was ahead is -54 km/h.

However, it is important to note that negative speeds do not make physical sense in this context. Therefore, we can conclude that there is an error in the given information or the problem statement.

Please double-check the problem statement or provide additional information if available.