Question

Решите пж (714-649)х7-(95:19)х(68:2) 6х(532-478)+(300-38х7):17 2448:3-5607:7+294 Помогите пж расписывая

Answer 1

6х(532-478)+(300-38х7):17=6×54+34÷17=324+2=326

2448:3-5607:7+294=816-801+294=309

Answer 2

Calculation

To solve the given expression, we'll follow the order of operations (PEMDAS/BODMAS: Parentheses/Brackets, Exponents/Orders, Multiplication and Division, Addition and Subtraction).

The given expression is: (714-649)×7-(95÷19)×(68÷2)+6×(532-478)+(300-38×7)÷17+2448÷3-5607÷7+294

Let's solve it step by step.

1. Subtraction within Parentheses - (714-649) = 65 - (532-478) = 54 - (300-38×7) = 46

2. Division - (95÷19) = 5 - (68÷2) = 34 - (300-38×7)÷17 = 2

3. Multiplication - 65×7 = 455 - 5×34 = 170 - 6×54 = 324 - 2×46 = 92 - 38×7 = 266 - 2448÷3 = 816 - 5607÷7 = 801

4. Final Calculation - 455 - 170 + 324 + 92 + 2 + 816 - 801 + 294 - 2162

Answer

The result of the given expression (714-649)×7-(95÷19)×(68÷2)+6×(532-478)+(300-38×7)÷17+2448÷3-5607÷7+294 is 2162.