Question

Из пункта А выехал мотоциклист со скоростью 110 км/ч в направлении к пункту В, а из пункта В одновременно с ним выехал другой мотоциклист в том же направлении со скоростью 90 км/ч . Первый мотоциклист догнал второго через полчаса. найдите расстояние между пунктами А и В. СРОЧНО ПЛИЗ

Answer 1

Пусть Х-искомое расстояние, тогда 
первый до встречи проехал 110*0,5=55 км
второй до встречи проехал 90*9,5=45 км
55-45=10 км
110*0,5=90*0,5+Х
Х=10 км

Answer 2

Problem Analysis

We are given that a motorcyclist leaves point A with a speed of 110 km/h towards point B, while another motorcyclist leaves point B simultaneously in the same direction with a speed of 90 km/h. The first motorcyclist catches up to the second motorcyclist after half an hour. We need to find the distance between points A and B.

Solution

Let's assume that the distance between points A and B is d kilometers.

Since the first motorcyclist catches up to the second motorcyclist after half an hour, we can set up the following equation based on their speeds and the time it took for the catch-up:

d = (110 km/h - 90 km/h) * (0.5 h)

Simplifying the equation, we get:

d = 20 km/h * 0.5 h

d = 10 km

Therefore, the distance between points A and B is 10 kilometers.

Answer

The distance between points A and B is 10 kilometers.