Question

Номер 1 Запишите сокращенна при помощи коэффициентов2(x+y)+3(x+z)-4(z+y)Номер 2 Решите уровнение 2(3/7х + 2)-3(1-х)=10+чПомогите пожалуйста

Answer 1

1)
2(х + у) + 3(х + z) - 4(z + у) = 2х + 2у + 3х + 3z - 4z - 4у = 3х - 2у - z

2) 2(3/7х + 2) - 3(1 - х) = 10 + х
6/7х + 4 - 3 + 3х - х = 10
2 6/7х = 10 - 1
20/7х = 9
х = 9 : 20/7
х = 9 * 7/20
х = 63/20
х = 3,15

Answer 2

Answer 1:

To simplify the expression 2(x+y) + 3(x+z) - 4(z+y), we can distribute the coefficients and combine like terms. Let's break it down step by step:

1. Distribute the coefficients: - 2(x+y) = 2x + 2y - 3(x+z) = 3x + 3z - 4(z+y) = 4z + 4y

2. Combine like terms: - 2x + 2y + 3x + 3z - 4z - 4y

Now, let's group the like terms together: - (2x + 3x) + (2y - 4y) + (3z - 4z)

Simplifying further: - 5x - 2y - z

Therefore, the simplified form of the expression 2(x+y) + 3(x+z) - 4(z+y) is 5x - 2y - z.