Question

Два трицифрові числа утворені з шести різних цифр.Перша цифра другого числа в два рази більша за останню цифру першого числа. Чому дорівнює найменша можлива сума двох таких чисел?

Answer 1

Ответ 537  ето правельно!

Answer 2

Problem Analysis

We are given that two three-digit numbers are formed using six different digits. The first digit of the second number is twice the last digit of the first number. We need to find the smallest possible sum of these two numbers.

Solution

To find the smallest possible sum of the two numbers, we need to minimize the individual digits of each number. Let's analyze the given information step by step:

1. We are forming two three-digit numbers using six different digits. This means that each number will have three unique digits.

2. The first digit of the second number is twice the last digit of the first number. Let's represent the digits of the first number as A, B, and C (from left to right). The second number will have the digits C, D, and 2C (from left to right).

3. Since we need to minimize the digits, we should assign the smallest possible values to A, B, and C. Let's assign A = 1, B = 2, and C = 3.

4. Using these values, the first number becomes 123, and the second number becomes 32D, where D = 2C = 2 * 3 = 6.

5. The smallest possible sum of these two numbers is 123 + 326 = 449.

Therefore, the smallest possible sum of two three-digit numbers formed using six different digits, where the first digit of the second number is twice the last digit of the first number, is 449.