Question

<p>Решите плиз задачу зарание большое спасибо! На стройку нужно привезти 180тонн кирпича.Большой самосвал может вывезти этот груз за 20 рейсов, а меньший самосвал за 30 рейсов.За сколько рейсов вывезут они этот груз, если будут работать вместе?</p> с условием

Answer 1

1)180/20=9
2)180/30=6
3)6+9=15
4)180/15=12
Ответ: за 12 рейсов.

Answer 2

Problem Analysis

To solve this problem, we need to determine how many trips it will take for two trucks, one large and one small, to transport a total of 180 tons of bricks. The large truck can transport the entire load in 20 trips, while the small truck can transport the entire load in 30 trips. We need to find the number of trips required when both trucks work together.

Solution

Let's assume that the number of trips required when both trucks work together is x.

Since the large truck can transport the entire load in 20 trips, it means that in one trip, it transports 180/20 = 9 tons of bricks.

Similarly, the small truck can transport the entire load in 30 trips, so in one trip, it transports 180/30 = 6 tons of bricks.

When both trucks work together, the total load transported in one trip is the sum of the loads transported by each truck. Therefore, the equation becomes:

9x + 6x = 180

Simplifying the equation:

15x = 180

Dividing both sides of the equation by 15:

x = 180/15

Therefore, the number of trips required when both trucks work together is 12 trips.

Answer

If the large truck can transport the entire load in 20 trips and the small truck can transport the entire load in 30 trips, then when both trucks work together, they will be able to transport the entire load in 12 trips.