
Из пункта А в пункт В вышел товарный поезд . Спустя 2ч вслед за ним вышел скорый поезд , который
шёл со скоростью , на 30 км\ч больше , чем товарный . Через 10ч после своего выхода скорый поезд , обогнав товарный , находился от него на расстоянии 220 км . Найти скорость товарного поезда . ПОМОГИТЕ ПОЖАЛУЙСТА РЕШИТЬ !!!!!!СРОЧНО !!!!

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Problem Analysis
We are given that a freight train left point A and after 2 hours, a fast train left point A as well. The fast train was traveling at a speed that was 30 km/h faster than the freight train. After 10 hours from its departure, the fast train overtook the freight train and was 220 km ahead of it. We need to find the speed of the freight train.Solution
Let's assume the speed of the freight train is x km/h. Since the fast train was traveling at a speed that was 30 km/h faster than the freight train, its speed would be x + 30 km/h.We can use the formula distance = speed × time to calculate the distances traveled by both trains.
The distance traveled by the freight train in 10 hours would be 10x km, and the distance traveled by the fast train in 10 hours would be 10(x + 30) km.
We are given that the fast train overtook the freight train and was 220 km ahead of it. This means that the distance traveled by the fast train is equal to the distance traveled by the freight train plus 220 km.
Setting up the equation: 10(x + 30) = 10x + 220
Simplifying the equation: 10x + 300 = 10x + 220 300 - 220 = 10x - 10x 80 = 0
Since the equation simplifies to 80 = 0, we can conclude that there is no solution to this equation. This means that there is no valid speed for the freight train that satisfies the given conditions.
Therefore, there is no solution to this problem.
Conclusion
There is no valid speed for the freight train that satisfies the given conditions.

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