Question

Велосипедист проехал путь от поселка до районного центра за 1 ч 30 мин.На обратном пути он увеличил скорость и поэтому весь путь проехал за 1 ч 15 мин. Во сколько раз скорость велосипедиста на обратном пути была больше первоначальной

Answer 1

1ч30мин=1,5ч1ч15мин=1,25ч1,5:1,25=1,2-во столько скорость велосипедиста на обратном пути больше первоначальнойОтвет:в 1,2 раз больше

Answer 2

Calculating the Increase in Speed of the Cyclist

To calculate the increase in speed of the cyclist on the return trip, we can use the formula:

Speed = Distance / Time

Let's denote: - Initial speed as S1 - Time taken for the initial trip as T1 - Distance covered in the initial trip as D - Increased speed on the return trip as S2 - Time taken for the return trip as T2

We are given: - T1 = 1 hour 30 minutes = 1.5 hours - T2 = 1 hour 15 minutes = 1.25 hours

Using the formula, we can calculate the speeds for the initial and return trips.

Calculating the Speed for the Initial Trip

S1 = D / T1

Calculating the Speed for the Return Trip

S2 = D / T2

Now, let's calculate the speeds for the initial and return trips using the given time values.

Calculation

S1 = D / 1.5 S2 = D / 1.25 By comparing the two speeds, we can find the ratio of the return trip speed to the initial trip speed.

Finding the Ratio

Ratio = S2 / S1

Let's calculate the ratio to determine how many times the speed on the return trip was greater than the initial speed.

Calculation

Ratio = (D / 1.25) / (D / 1.5)

By simplifying the expression, we can find the ratio.

Simplifying the Expression

Ratio = (1.5) / (1.25) = 6 / 5

So, the speed of the cyclist on the return trip was 6/5 times or 1.2 times greater than the initial speed.

Therefore, the speed of the cyclist on the return trip was 1.2 times greater than the initial speed.