Question

Какова вероятность того что наугад выбранное двузначное число кратное числу 11???

Answer 1

$P(A) = \frac{m}{n} = \frac{9}{90} = \frac{1}{10} = 0,1$

Answer 2

Probability of Selecting a Two-Digit Number Divisible by 11

The probability of randomly selecting a two-digit number that is divisible by 11 can be calculated by determining the number of two-digit multiples of 11 and then comparing it to the total number of two-digit numbers.

Step 1: Counting Two-Digit Multiples of 11 There are 9 two-digit multiples of 11, ranging from 11 to 99. These are: 11, 22, 33, 44, 55, 66, 77, 88, and 99.

Step 2: Counting Total Two-Digit Numbers The total number of two-digit numbers is 90, as they range from 10 to 99.

Step 3: Calculating Probability The probability of selecting a two-digit number that is divisible by 11 is the ratio of the number of two-digit multiples of 11 to the total number of two-digit numbers. Therefore, the probability is:

\[ \frac{9}{90} = \frac{1}{10} \]

So, the probability of randomly selecting a two-digit number that is divisible by 11 is 1/10.