Question

Решите пожалуйста 8 задание

Answer 1

Дысь, фотографию то го?!

Answer 2

Где? Задание, фотку можно,

Answer 3

Task 8 Solution

To solve the given task, we need to analyze the provided mathematical equations and find the values of variables x and y.

The given equations are: 1. \( x^2 + y^2 = 20 \) 2. \( 3x + y = 2 \) 3. \( \frac{1}{x} - \frac{1}{y} = \frac{1}{6} \)

Solution Steps:

1. Solving for x and y in Equations 1 and 2: - From Equation 2, we can express \( y \) in terms of \( x \): \( y = 2 - 3x \). - Substituting this value of \( y \) into Equation 1, we get a quadratic equation in terms of \( x \). - Solving the quadratic equation will give us the values of \( x \), and then we can find the corresponding values of \( y \).

2. Solving for x and y in Equations 4 and 5: - We have a system of two equations: \( xy - 3y^2 = -24 \) and \( xy + 2y^2 = 21 \). - We can solve this system of equations to find the values of \( x \) and \( y \).

Let's solve these step by step.

Solving Equations 1 and 2:

- From Equation 2, \( y = 2 - 3x \). - Substituting this value of \( y \) into Equation 1, we get: \[ x^2 + (2 - 3x)^2 = 20 \] \[ 10x^2 - 12x - 16 = 0 \]

Using the quadratic formula, we can solve for \( x \): \[ x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}} \]

After finding the values of \( x \), we can find the corresponding values of \( y \) using \( y = 2 - 3x \).

Solving Equations 4 and 5:

- We have the system of equations: \[ xy - 3y^2 = -24 \] \[ xy + 2y^2 = 21 \]

We can solve this system of equations to find the values of \( x \) and \( y \).

Let's calculate the values of \( x \) and \( y \) using the above steps.