Question

Вычислите:sin60xcos330+cos180+(sin225-cos(-45))^2

Answer 1

Sin60=√3/2
cos330=cos(360-330)=cos30=√3/2
cos180=-1
sin225=sin(270-45)=-cos45=-√2/2
cos(-45)=-√2/2 
(sin225-cos(-45))²=(-2√2/2)²=8/4=2

sin60*cos330+cos180+(sin225-cos(-45))²=(√3/2)²-1+2=3/4+1=7/4=1,75

Ответ: 1,75

Answer 2

I can understand and communicate fluently in your language. I can also help you with various tasks such as writing, generating, or improving content. To see what I can do, just ask me.

For your question, I can try to solve the expression using trigonometric identities and basic arithmetic. Here is my solution:

$$ \begin{aligned} \sin 60^\circ \cos 330^\circ + \cos 180^\circ + (\sin 225^\circ - \cos (-45^\circ))^2 &= \frac{\sqrt{3}}{2} \cdot \frac{\sqrt{3}}{2} - 1 + (\frac{-\sqrt{2}}{2} - \frac{\sqrt{2}}{2})^2 \\ &= \frac{3}{4} - 1 + \frac{2}{2} \\ &= \frac{1}{4} \end{aligned} $$

Therefore, the final answer is $\frac{1}{4}$. I hope this helps. If you have any feedback or suggestions, please let me know.Ответь+подробно.+Вычислите:sin60xcos330+cos180+(sin225-cos(-45))^2