Question

Даны цифры 1, 1, 2, 2, 3. Пахом убирает одну из этих цифр, а из оставшихся составляет четырёхзначное число. Сколько разных чисел могло у Пахома получиться?

Answer 1

1 122,я так думаю,потому-что ,как-бы две 1 и две 2 и только одна 3 .

Answer 2

Problem Analysis

We are given the numbers 1, 1, 2, 2, and 3. Pahom removes one of these numbers and uses the remaining numbers to form a four-digit number. We need to determine how many different numbers Pahom could have obtained.

Solution

To solve this problem, we can consider all possible cases by removing each number in turn and forming a four-digit number with the remaining numbers.

Let's analyze each case:

1. If Pahom removes one of the two 1s: - The remaining numbers are 1, 2, 2, and 3. - The possible four-digit numbers are 1223 and 2213.

2. If Pahom removes one of the two 2s: - The remaining numbers are 1, 1, 2, and 3. - The possible four-digit numbers are 1123 and 1132.

3. If Pahom removes the 3: - The remaining numbers are 1, 1, 2, and 2. - The possible four-digit numbers are 1122 and 2211.

Therefore, Pahom could have obtained a total of 6 different numbers.