Question

Построить график y=log2(x-3)+1

Answer 1

Строим y=log(2)x
x    1/2    1      2      4      8
y    -1      0      1      2      3
Cдвигаем ось оу на 3 единицы влево,а ось ох на единицу вниз

Answer 2

Plotting the Graph of y = log2(x-3) + 1

To plot the graph of the function y = log2(x-3) + 1, we can start by identifying some key points on the graph.

Let's consider a few values of x and calculate the corresponding values of y:

- For x = 1, y = log2(1-3) + 1 = log2(-2) + 1. However, the logarithm of a negative number is undefined, so we cannot calculate the value of y for x = 1. - For x = 2, y = log2(2-3) + 1 = log2(-1) + 1. Again, the logarithm of a negative number is undefined, so we cannot calculate the value of y for x = 2. - For x = 3, y = log2(3-3) + 1 = log2(0) + 1. The logarithm of zero is also undefined, so we cannot calculate the value of y for x = 3. - For x = 4, y = log2(4-3) + 1 = log2(1) + 1 = 0 + 1 = 1. - For x = 5, y = log2(5-3) + 1 = log2(2) + 1 = 1 + 1 = 2.

Based on these calculations, we have the following points on the graph:

- (4, 1) - (5, 2)

Now, let's plot these points on a graph:


Please note that the graph may not be accurate as the exact values of y for x = 1, 2, and 3 are undefined.

I hope this helps! Let me know if you have any further questions.