Question

Из двух городов, расстояние между которыми 270 км, одновременно навстречу друг другу выехали два поезда. Пассажирский поезд шёл со скоростью 40км/ч . Чему равна скорость скорого поезда, если поезда встретились через 3 часа? Помогите решить задачу пож

Answer 1

1) 40*3=120 км- прошел пассажирский
2)270-120=150км - прошел скорый
3)150/3=50км/ч
ответ: скорость скорого поезда равна 50км/ч

Answer 2

Problem Analysis

We are given that two trains start simultaneously from two cities that are 270 km apart and are moving towards each other. The passenger train is traveling at a speed of 40 km/h. We need to find the speed of the other train if they meet after 3 hours.

Solution

Let's assume the speed of the other train is x km/h.

To solve this problem, we can use the formula: Distance = Speed × Time.

The distance covered by the passenger train in 3 hours is 40 km/h × 3 h = 120 km.

The distance covered by the other train in 3 hours is x km/h × 3 h = 3x km.

Since the total distance between the two cities is 270 km, the sum of the distances covered by both trains should be equal to 270 km.

Therefore, we can write the equation: 120 km + 3x km = 270 km.

Simplifying the equation, we get: 3x km = 150 km.

Dividing both sides of the equation by 3, we find: x km = 50 km/h.

Therefore, the speed of the other train is 50 km/h.

Answer

The speed of the faster train is 50 km/h.