Question

Мотоциклист двигался по дороге с постояной скоростью. В первый день он проехал 900км в ч во 2 750. Во 2 день он был в пути на 3 часа меньше чем в первый. в 3 день мотоциклист был в пути 7 часов. Какое расстояние преодолел мотоциклист в 3 день?

Answer 1

В 1день проехал 1 часть пути
во 2 день 2части пути (по условию)
2+1=3 части пути за 2 дня
840:3=280км-1 часть -то есть путь в 1 день
280*2=560км -2 части -то есть путь во 2 день
280:4=70км в час-скорость в 1 день
560:10=56 км в час -скорость во 2 день

Answer 2

Calculation of the Distance Traveled by the Motorcyclist on the Third Day

To calculate the distance traveled by the motorcyclist on the third day, we need to analyze the information provided.

On the first day, the motorcyclist traveled 900 km in 3 hours, which means their speed was 900 km / 3 hours = 300 km/h.

On the second day, the motorcyclist was in transit for 3 hours less than on the first day. Let's denote the time traveled on the second day as t. Therefore, the time traveled on the second day can be expressed as t = 3 hours - 3 hours = 0 hours.

On the third day, the motorcyclist was in transit for 7 hours.

To calculate the distance traveled on the third day, we can use the formula:

Distance = Speed × Time

Since the motorcyclist traveled at a constant speed, we can use the speed calculated on the first day, which is 300 km/h.

Substituting the values into the formula, we get:

Distance = 300 km/h × 7 hours = 2100 km

Therefore, the motorcyclist traveled a distance of 2100 km on the third day.