Question

Длина прямоугольника 50 дм....ширина 10 дм.найди периметр и площадь прямоугольника

Answer 1

Р=(50+10)×2=120
S=50×10=500

Answer 2

1) P=(50+10)*2=120дм
2) S=50*10=500дм
Ответ:120дм, 500дм

Answer 3

Calculation of Perimeter and Area of a Rectangle

To find the perimeter and area of a rectangle, we need to know the length and width of the rectangle. In this case, the length of the rectangle is 50 dm and the width is 10 dm.

Perimeter is the distance around the outside of a shape. For a rectangle, the perimeter is calculated by adding the lengths of all four sides. The formula for the perimeter of a rectangle is:

Perimeter = 2 * (Length + Width)

Substituting the given values, we have:

Perimeter = 2 * (50 dm + 10 dm)

To calculate the perimeter, we can use the formula:

Perimeter = 2 * (Length + Width)

Substituting the given values, we have:

Perimeter = 2 * (50 dm + 10 dm)

Perimeter = 2 * (60 dm)

Perimeter = 120 dm

Therefore, the perimeter of the rectangle is 120 dm.

Area is the measure of the space inside a shape. For a rectangle, the area is calculated by multiplying the length and width. The formula for the area of a#### Calculating Perimeter and Area of a Rectangle

To find the perimeter and area of a rectangle with a length of 50 dm and a width of 10 dm, we can use the following formulas:

Perimeter of a Rectangle: The perimeter (P) of a rectangle is given by the formula: P = 2 * (length + width).

Area of a Rectangle: The area (A) of a rectangle is given by the formula: A = length * width.

Calculations

Using the given length and width: - Length (l) = 50 dm - Width (w) = 10 dm

Perimeter: P = 2 * (l + w) P = 2 * (50 + 10) P = 2 * 60 P = 120 dm

Area: A = l * w A = 50 * 10 A = 500 square dm

So, the perimeter of the rectangle is 120 dm and the area is 500 square dm.