Question

Помогите , годовая!!!! Постройте график функции y=-2x+3. Найдите точки пересечения графика с осью Оу

Answer 1

Точки для построения:

х        у
-3      9
0       3
2        -1

сам график в приложенном файле

Answer 2

Building the Graph of y = -2x + 3 and Finding Intersection Points with the y-axis

To build the graph of the function y = -2x + 3, we can start by finding the points of intersection with the y-axis. The y-axis is where x = 0, so we can substitute x = 0 into the equation to find the y-coordinate of the point of intersection.

Substituting x = 0 into the equation: y = -2(0) + 3 y = 3

So, the point of intersection with the y-axis is (0, 3).

Now, let's plot this point and draw the graph of the function.

Point of intersection with the y-axis: (0, 3)

Graph of y = -2x + 3

Now, let's plot the graph of the function y = -2x + 3. The graph is a straight line with a slope of -2 and a y-intercept of 3.

The graph is a straight line with a slope of -2 and a y-intercept of 3.

Conclusion

By plotting the point of intersection with the y-axis and drawing the graph of the function y = -2x + 3, we have visualized the function and its behavior. If you have any further questions or need additional assistance, feel free to ask!