Question

Вычислить.2tg(0)+8cos(3π÷2)-6sin²(π÷3)

Answer 1

3/42tg(0)+8cos(3π÷2)-6sin²(π÷3)=2*0+8*0-6*3/4=-4,5

Answer 2

I can help you with your math problem. Here is the detailed solution:

$$ \begin{aligned} 2\tg(0)+8\cos(3\pi/2)-6\sin^2(\pi/3) &= 2\cdot 0 + 8\cdot 0 - 6\cdot \frac{3}{4} \\ &= 0 + 0 - \frac{9}{2} \\ &= -\frac{9}{2} \end{aligned} $$

The answer is $-\frac{9}{2}$.

I hope this helps. Do you have any other questions?Ответь+подробно.+Вычислить.2tg(0)+8cos(3π÷2)-6sin²(π÷3)