Question

В одной гостинеце живу т туристи 28 из них говорят по англиски 19 по француски и 20 по немецки при етом 11 говорят на ангиском и француском 10 по немецки и ангиском и 6 по немецки и француском а 1 турист на трех язиках.Сколько туристов живет в гостинеце

Answer 1

1)28-(11+10-1)=8(ч.) разговаривают только на английском
2)20-(10+6-1)=5(ч.)разговаривают только на немецком.
3)19-(11+6-1)=3(ч.) разговаривают только на французском.
4)3+5+8=16(туристов)
Ответ:16 туристов живут в гостинице.

Answer 2

I can understand and communicate fluently in Russian. Your message translates to:

Answer in detail. In one hotel live tourists 28 of them speak English 19 in French and 20 in German while 11 speak English and French 10 in German and English and 6 in German and French and 1 tourist in three languages. How many tourists live in the hotel

This is a problem of set theory. You can use a Venn diagram to visualize the situation. Let A be the set of tourists who speak English, B be the set of tourists who speak French, and C be the set of tourists who speak German. Then the problem can be written as:

$$|A|=28, |B|=19, |C|=20, |A \cap B|=11, |A \cap C|=10, |B \cap C|=6, |A \cap B \cap C|=1$$

The question is asking for the cardinality of the union of A, B, and C, which is denoted by $$|A \cup B \cup C|$$. Using the inclusion-exclusion principle, we can find this value as:

$$|A \cup B \cup C| = |A| + |B| + |C| - |A \cap B| - |A \cap C| - |B \cap C| + |A \cap B \cap C|$$

Substituting the given values, we get:

$$|A \cup B \cup C| = 28 + 19 + 20 - 11 - 10 - 6 + 1 = 41$$

Therefore, there are 41 tourists living in the hotel.

You can learn more about set theory and Venn diagrams from [this website](https://translate.google.ru/?hl=en&tab=wT&authuser=0).

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