Вопрос задан 27.04.2019 в 23:26. Предмет Математика. Спрашивает Плетнёва Аля.

Решите задачу На складе было 270т картофеля.В начале вывезли 5/9 этого картофеля,а во второй раз

вывезли 0,45 того что вывезли в первый раз.Какую часть всего картофеля вывезли во второй раз?сколько тон картофеля осталось на складе? 2 способоми
0 0
Перейти к ответам

Ответы на вопрос

Внимание! Ответы на вопросы дают живые люди. Они могут содержать ошибочную информацию, заблуждения, а также ответы могут быть сгенерированы нейросетями. Будьте внимательны. Если вы уверены, что ответ неверный, нажмите кнопку "Пожаловаться" под ответом.
Отвечает Маматова Екатерина.
1)270:9*5=150т-вывезли сначала.
2)150*0.45=67.5т-вывезли во второй раз.
3)67.5:270=0.25=1\4часть-вывезли во второй раз.
4)270-(150+67.5)=52.5т-осталось.

1)5\9*0.45=1\4часть-вывезли во второй раз.
2)5\9+1\4=20\36+9\36=29\36 картофеля-вывезли всего.
3)270:36*29=217.5т-вывезли всего.
4)270-217.5=52.5т-осталось.
0 0
Отвечает Шишкина Ксения.
(270:9)*5=150
150:100*45=27
270 - 150 - 27 = 93
Ответ: 1\10 ,  92 т.

0 0
Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Problem Analysis

To solve this problem, we need to determine the fraction of the total potatoes that were taken out on the second occasion and calculate the amount of potatoes that remained on the storage.

Solution

Let's break down the problem step by step:

1. Initially, there were 270 tons of potatoes on the storage. 2. On the first occasion, 5/9 of the potatoes were taken out. To calculate this, we multiply 270 by 5/9: 270 * 5/9 = 150 tons of potatoes were taken out on the first occasion. 3. On the second occasion, 0.45 (45%) of the potatoes that were taken out on the first occasion were taken out. To calculate this, we multiply 150 by 0.45: 150 * 0.45 = 67.5 tons of potatoes were taken out on the second occasion. 4. To determine the fraction of the total potatoes that were taken out on the second occasion, we divide the amount taken out on the second occasion by the initial amount of potatoes: 67.5 / 270 = 0.25 (or 25%). 5. To calculate the amount of potatoes that remained on the storage, we subtract the total amount taken out from the initial amount: 270 - (150 + 67.5) = 52.5 tons of potatoes remained on the storage.

Therefore, 25% of the total potatoes were taken out on the second occasion, and 52.5 tons of potatoes remained on the storage.

Alternative Method

Another way to solve this problem is by calculating the amount of potatoes taken out on the second occasion directly.

1. Initially, there were 270 tons of potatoes on the storage. 2. On the first occasion, 5/9 of the potatoes were taken out. To calculate this, we multiply 270 by 5/9: 270 * 5/9 = 150 tons of potatoes were taken out on the first occasion. 3. On the second occasion, 0.45 (45%) of the potatoes that were taken out on the first occasion were taken out. To calculate this, we multiply 150 by 0.45: 150 * 0.45 = 67.5 tons of potatoes were taken out on the second occasion.

Therefore, 67.5 tons of potatoes were taken out on the second occasion.

To calculate the amount of potatoes that remained on the storage, we subtract the total amount taken out from the initial amount: 270 - (150 + 67.5) = 52.5 tons of potatoes remained on the storage.

Using this alternative method, we still find that 52.5 tons of potatoes remained on the storage.

I hope this helps! Let me know if you have any further questions.

0 0

Топ вопросов за вчера в категории Математика

Последние заданные вопросы в категории Математика

Задать вопрос