Question

За месяц съели 20 кг картофеля. Это пятая часть от всего запаса картофеля. Сколько картофеля было первоночально.? Бригаде надо заасфальтировать 20 км дороги. В первый день бригада заасфальтировала четвертую часть дороги. Во сколько раз заасфальтированная часть дороги меньше той части которую надо ещё заасфальтироват?

Answer 1

1
1)20*5=100
2
1)20:4=5-в 1 день
2)20:5=4-в 4 раза меньше

Answer 2

Calculation of Initial Potato Stockpile

To find out the initial amount of potatoes, we can use the information given in the question. It states that 20 kg of potatoes were consumed, which is one-fifth (or the fifth part) of the total potato stockpile.

Let's assume the initial amount of potatoes as 'P'. According to the information given, 20 kg is one-fifth of the total stockpile:

20 kg = (1/5) * P

To find the value of 'P', we can multiply both sides of the equation by 5:

5 * 20 kg = P

Simplifying the equation:

100 kg = P

Therefore, the initial amount of potatoes was 100 kg.

Calculation of Remaining Road to be Paved

The question states that a brigade needs to pave 20 km of road. On the first day, they paved one-fourth (or the fourth part) of the road. We need to find out how many times the paved part is smaller than the remaining part.

Let's assume the total length of the road as 'R'. According to the information given, one-fourth of the road was paved on the first day:

1/4 * R = Paved part of the road

To find the remaining part of the road, we can subtract the paved part from the total length:

Remaining part of the road = R - Paved part of the road

Simplifying the equation:

Remaining part of the road = R - (1/4 * R)

To calculate the ratio between the paved part and the remaining part, we can divide the remaining part by the paved part:

Ratio = Remaining part of the road / Paved part of the road

Substituting the values:

Ratio = (R - (1/4 * R)) / (1/4 * R)

Simplifying the equation:

Ratio = (3/4 * R) / (1/4 * R)

Simplifying further:

Ratio = (3/4) / (1/4)

Dividing the fractions:

Ratio = (3/4) * (4/1) = 3

Therefore, the paved part of the road is three times smaller than the remaining part.

Conclusion

- The initial amount of potatoes was 100 kg. - The paved part of the road is three times smaller than the remaining part.