Question

От пристани одновремено в провотиположных направлениях выехали две моторные лодки. Через 3ч расстояние между ними было равно 168 км.Какова скорость первой лодки если скорость второй лодки 27 км/ч.Ребят помогите пожалуйста дам много баллов

Answer 1

Общая скорость: 168/3 = 56(км/ч)
Скорость первой лодки: 56-27=29(км/ч)
Ответ: 29 км/ч

Answer 2

168:3=56 (км/ч) скорость удаления или сумма скоростей
56-27=29 (км/ч)
Ответ: скорость первой лодки 29 км/ч

Answer 3

Problem Analysis

We are given that two motorboats left a pier simultaneously in opposite directions. After 3 hours, the distance between them was 168 km. We are also given that the speed of the second boat is 27 km/h. We need to find the speed of the first boat.

Solution

Let's assume the speed of the first boat is x km/h.

We know that the distance traveled by an object is equal to its speed multiplied by the time taken. Therefore, the distance traveled by the first boat in 3 hours is 3x km.

Since the two boats are moving in opposite directions, the total distance between them after 3 hours is the sum of the distances traveled by each boat. This can be represented as:

3x + 3(27) = 168

Simplifying the equation:

3x + 81 = 168

Subtracting 81 from both sides:

3x = 87

Dividing both sides by 3:

x = 29

Therefore, the speed of the first boat is 29 km/h.

Answer

The speed of the first boat is 29 km/h.