
+44-(-44)=? -26-26=? 82-(-18)=? (-11)-(-11)=? -23-(-55)=? Решите примеры для контрольной работы за
6 класс

Ответы на вопрос

-26-26=-26+(-26)=-52
82-(-18)=82+18=100
(-11)-(-11)=-11+11=0 -23-(-55)=-23+55=32
- и - дают +(1 пример,3,4)
- и + дают минус



Calculation of Expressions
Let's calculate the given expressions step by step:
1. 44 - (-44): - Subtracting a negative number is the same as adding its positive counterpart. - Therefore, 44 - (-44) is equivalent to 44 + 44. - The result is 88.
2. -26 - 26: - Subtracting a number from itself always results in zero. - Therefore, -26 - 26 is equal to 0.
3. 82 - (-18): - Subtracting a negative number is the same as adding its positive counterpart. - Therefore, 82 - (-18) is equivalent to 82 + 18. - The result is 100.
4. (-11) - (-11): - Subtracting a negative number is the same as adding its positive counterpart. - Therefore, (-11) - (-11) is equivalent to (-11) + 11. - The result is 0.
5. -23 - (-55): - Subtracting a negative number is the same as adding its positive counterpart. - Therefore, -23 - (-55) is equivalent to -23 + 55. - The result is 32.
Examples for 6th Grade Exam
Here are some examples for a 6th-grade exam:
1. Calculate the perimeter of a rectangle with a length of 8 cm and a width of 5 cm. - The perimeter of a rectangle is calculated by adding the lengths of all its sides. - In this case, the length is 8 cm and the width is 5 cm. - The perimeter is calculated as 2 * (length + width) = 2 * (8 + 5) = 2 * 13 = 26 cm.
2. Solve the equation: 3x + 5 = 20. - To solve this equation, we need to isolate the variable x. - Subtract 5 from both sides of the equation: 3x = 20 - 5 = 15. - Divide both sides of the equation by 3: x = 15 / 3 = 5.
3. Find the area of a triangle with a base of 6 cm and a height of 9 cm. - The area of a triangle is calculated by multiplying the base by the height and dividing by 2. - In this case, the base is 6 cm and the height is 9 cm. - The area is calculated as (base * height) / 2 = (6 * 9) / 2 = 54 / 2 = 27 cm².
These examples should help you prepare for your 6th-grade exam. Good luck!


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