Question

Помогите пожалуйста решить задачу. В трёх корзинах лежали грибы. Из первой корзины взяли 25 грибов, из второй -19 грибов , а в третью положили 27 грибов. В трёх корзинах стало 83 гриба. Сколько всего грибов было в трёх корзинах сначала.

Answer 1

83-27+19+25=100 грибов было изначально в корзинах
Задача решается с конца.

Проверка
100-25=75
75-19=56
56+27=83

Answer 2

Problem Analysis

To solve this problem, we need to determine the initial number of mushrooms in the three baskets. We know that 25 mushrooms were taken from the first basket, 19 mushrooms were taken from the second basket, and 27 mushrooms were added to the third basket. After these operations, there were a total of 83 mushrooms in the three baskets. We need to find the initial number of mushrooms in the three baskets.

Solution

Let's assume the initial number of mushrooms in the first basket is x, in the second basket is y, and in the third basket is z.

From the given information, we can form the following equations:

Equation 1: x - 25 = 0 (25 mushrooms were taken from the first basket) Equation 2: y - 19 = 0 (19 mushrooms were taken from the second basket) Equation 3: z + 27 = 83 (27 mushrooms were added to the third basket, resulting in a total of 83 mushrooms)

To find the initial number of mushrooms in the three baskets, we need to solve these equations simultaneously.

Solving the Equations

Let's solve the equations to find the values of x, y, and z.

From Equation 1, we have: x - 25 = 0 x = 25

From Equation 2, we have: y - 19 = 0 y = 19

From Equation 3, we have: z + 27 = 83 z = 83 - 27 z = 56

Therefore, the initial number of mushrooms in the three baskets were: - First basket: 25 mushrooms - Second basket: 19 mushrooms - Third basket: 56 mushrooms

Answer

The initial number of mushrooms in the three baskets were: - First basket: 25 mushrooms - Second basket: 19 mushrooms - Third basket: 56 mushrooms