Question

У Сережи в коллекции в 3 раза меньше марок, чем у Васи, а у Андрея в 2 раза больше, чем у Васи. Сколько марок у каждого, если у Андрея на 80 марок больше, чем у Сережи? с решением

Answer 1

3C=B 2B=A A-C=80 6C=2B=A ПОДСТАВИМ В МЕСТО A 6*C 6*C-C=80 5*C=80 C=16 МАРОК 16*3=48 МАРОК У В 48*2=96 МАРОК У А

Answer 2

Пусть у Серёжи Х марок, тогда у Васи 3*Х марок,а у Андрея 6*Х марок составляем уравнение: Х+80=6*Х переносим Х в левую часть, получаем 80=6*Х-Х , или, что то же самое, 5*Х=80 Х=80:5 Х=16 Следовательно, у Серёжи 16 марок, у Васи 16*3=48 марок, у Андрея 16*6=96 марок. Усё!

Answer 3

Problem Analysis

We are given the following information: - Sergey has three times fewer stamps than Vasya. - Andrei has twice as many stamps as Vasya. - Andrei has 80 more stamps than Sergey.

We need to determine the number of stamps each person has.

Solution

Let's assume that Vasya has x stamps.

According to the given information: - Sergey has three times fewer stamps than Vasya, so Sergey has x/3 stamps. - Andrei has twice as many stamps as Vasya, so Andrei has 2x stamps. - Andrei has 80 more stamps than Sergey, so 2x = x/3 + 80.

To solve this equation, we can multiply both sides by 3 to eliminate the fraction: 6x = x + 240.

Simplifying the equation, we get: 5x = 240.

Dividing both sides by 5, we find: x = 48.

Therefore, Vasya has 48 stamps, Sergey has 16 stamps (3 times fewer than Vasya), and Andrei has 96 stamps (twice as many as Vasya).

Answer

Vasya has 48 stamps, Sergey has 16 stamps, and Andrei has 96 stamps.