Question

7х(6х-5)+42х=3х(5+14х)+49 Помогите решить, заранее спасибо

Answer 1

1. Раскрываем скобки
42х^2-35х+42х=15х+42х^2+49
Все в одну сторону,и приводим подобные.
42х^2-35х+42-15х-42х^2-49=0 (42х^2 сокращаются)
Получается простое линейное уравнение
-8х-49=0
-8х=49
х=-6,125

Answer 2

To solve the equation 7x(6x-5) + 42x = 3x(5+14x) + 49, we will follow the steps below:

Step 1: Distribute the terms on both sides of the equation. - On the left side, distribute 7x to both terms inside the parentheses: 7x * 6x = 42x^2 and 7x * -5 = -35x. - On the right side, distribute 3x to both terms inside the parentheses: 3x * 5 = 15x and 3x * 14x = 42x^2.

The equation becomes: 42x^2 - 35x + 42x = 15x + 42x^2 + 49.

Step 2: Combine like terms on both sides of the equation. - On the left side, combine the x terms: -35x + 42x = 7x. - On the right side, combine the x terms: 15x + 42x = 57x. - The equation becomes: 42x^2 + 7x = 57x + 42x^2 + 49.

Step 3: Simplify the equation. - Subtract 57x and 42x^2 from both sides of the equation to eliminate those terms. - The equation becomes: 7x = 49.

Step 4: Solve for x. - Divide both sides of the equation by 7 to isolate x. - The solution is: x = 7.

Therefore, the solution to the equation 7x(6x-5) + 42x = 3x(5+14x) + 49 is x = 7.