Question

В трех бидонах вместе 178 кг масла. Масса масла в 1 бидоне составляет 6/7 массы масла во 2 бидоне, масса масла в 3 бидоне составляет 80% массы масла в 1 бидоне. Какая масса масла в каждом бидоне?

Answer 1

Х-масса масла в 1 бидоне
у-масса масла во втором бидоне
z- масса масла в третьем бидоне
Тогда:
x=6/7y; у=7х/6
z=0.8x
x+7x/6+0.8x=178
6x+7x+4.8x=1068
17.8x=1068
x=60
y=70
z=48

Answer 2

Calculation of Oil Mass in Each Canister

To find the mass of oil in each canister, we can set up a system of equations based on the given information.

Let's assume the mass of oil in the first canister is x kg. According to the problem, the mass of oil in the second canister is 6/7 times the mass of oil in the first canister. Therefore, the mass of oil in the second canister is (6/7)x kg.

The mass of oil in the third canister is stated to be 80% of the mass of oil in the first canister. Therefore, the mass of oil in the third canister is 0.8x kg.

According to the problem, the sum of the masses of oil in all three canisters is 178 kg. We can write this as an equation:

x + (6/7)x + 0.8x = 178

To solve this equation, we can combine like terms:

2.457x = 178

Now, we can solve for x:

x = 178 / 2.457

Evaluating this expression, we find that x ≈ 72.53 kg.

Therefore, the mass of oil in each canister is approximately as follows:

- First canister: 72.53 kg - Second canister: (6/7) * 72.53 ≈ 62.18 kg - Third canister: 0.8 * 72.53 ≈ 58.02 kg

Please note that the values are approximate due to rounding.

Let me know if there's anything else I can help you with!