Question

Длина прямоугольника 56 см. Ширина составляет 7/8 длины. Найдите периметр и площадь прямоугольника

Answer 1

56*7/8 = 49 см - ширина
(56+49)*2 = 112 + 98 = 210 см - периметр
56*49 = 2744 см^2 - площадь

Answer 2

Calculating the Perimeter and Area of a Rectangle

To find the perimeter and area of the given rectangle with a length of 56 cm and a width of 7/8 of the length, we can follow these steps:

1. Calculate the Width of the Rectangle: - The width of the rectangle is 7/8 of the length. - Therefore, the width = 7/8 * 56.

2. Calculate the Perimeter of the Rectangle: - The perimeter of a rectangle is given by the formula: P = 2 * (length + width).

3. Calculate the Area of the Rectangle: - The area of a rectangle is given by the formula: A = length * width.

Let's calculate the width, perimeter, and area of the rectangle using the given information.

Calculations

1. Calculate the Width of the Rectangle: - Width = 7/8 * 56 - Width = 49 cm

2. Calculate the Perimeter of the Rectangle: - Perimeter (P) = 2 * (length + width) - P = 2 * (56 + 49) - P = 2 * 105 - P = 210 cm

3. Calculate the Area of the Rectangle: - Area (A) = length * width - A = 56 * 49 - A = 2744 sq. cm

Results

- The width of the rectangle is 49 cm. - The perimeter of the rectangle is 210 cm. - The area of the rectangle is 2744 sq. cm.