Question

Играя в прятки со своей подругой, обезьянка пробежала 5 м по спине змеи и взобралась на самый верх пальмы, под которой отдыхала змея.Оставаясь на той же высоте, обезьянка перепрыгнула на соседнее дерево, которое стояло в 3 м от пальмы.Какой высоты была пальма, если обезьянка проделала путь в 15 м?

Answer 1

Змея была под пальмой
15-5=10
10-3=7

Answer 2

Problem Analysis

The problem states that while playing hide-and-seek with her friend, a monkey ran 5 meters along the snake's back and climbed to the top of a palm tree under which the snake was resting. The monkey then jumped to a neighboring tree, which was 3 meters away from the palm tree, while maintaining the same height. We need to determine the height of the palm tree if the monkey traveled a total distance of 15 meters.

Solution

Let's assume the height of the palm tree is h meters.

The monkey initially ran 5 meters along the snake's back and then climbed to the top of the palm tree. So, the monkey traveled a vertical distance of h meters.

Next, the monkey jumped to a neighboring tree, which was 3 meters away from the palm tree. Since the monkey maintained the same height, the vertical distance traveled is still h meters.

Therefore, the total vertical distance traveled by the monkey is 2 times the height of the palm tree, which is 2h meters.

According to the problem, the monkey traveled a total distance of 15 meters. This includes the horizontal distance of 3 meters between the trees and the vertical distance of 2h meters.

So, we can set up the following equation:

2h + 3 = 15

Simplifying the equation:

2h = 12

h = 6

Therefore, the height of the palm tree is 6 meters.

Answer

The height of the palm tree is 6 meters.

Verification

To verify the answer, let's substitute the value of h into the equation:

2h + 3 = 15

2(6) + 3 = 15

12 + 3 = 15

15 = 15

The equation holds true, confirming that the height of the palm tree is indeed 6 meters.