Question

Два стрільця незалежно один від одного стріляють у ціль . ймовірність попадання в ціль першого стрільця дорівнює 0,8 а другого - 0,7 . яка ймовірність того , що один стрілець промахнеться а другий попаде в ціль

Answer 1

1й попал = 0,8

1й промах = 0,2

2й попал = 0,7

2й промах = 0,3

 

(1й попал И 2й промах) ИЛИ ((1й промах И 2й попал)

 

 

(0,8 * 0,3) + (0,7 * 0,2)

0,24 + 0,14 = 0,38

 

 

 

 

 

 

 

 

Answer 2

Probability of One Marksman Missing and the Other Hitting the Target

When two marksmen independently shoot at a target, the probability of one marksman missing and the other hitting the target can be calculated using the concept of complementary events.

Let's denote the probability of the first marksman hitting the target as P(A) = 0.8 and the probability of the second marksman hitting the target as P(B) = 0.7.

The probability of the first marksman missing the target is the complement of the probability of hitting the target, which is 1 - P(A) = 1 - 0.8 = 0.2. Similarly, the probability of the second marksman missing the target is 1 - P(B) = 1 - 0.7 = 0.3.

Now, we can calculate the probability of one marksman missing and the other hitting the target using the probabilities of missing and hitting for each marksman.

The probability of the first marksman missing and the second hitting is given by: P(A' ∩ B) = P(A') * P(B) = 0.2 * 0.7 = 0.14

Similarly, the probability of the first hitting and the second missing is given by: P(A ∩ B') = P(A) * P(B') = 0.8 * 0.3 = 0.24

Finally, the total probability of one marksman missing and the other hitting the target is the sum of these two probabilities: P(A' ∩ B) + P(A ∩ B') = 0.14 + 0.24 = 0.38

Therefore, the probability that one marksman will miss and the other will hit the target is 0.38.