Question

4у+10>_ 2 (1-у)+24= 49-3 (3-2z)<_1-4z = 7×(6-5t)-5 <1-41t= -0,5 (8x+9)-0,9>4x-3=

Answer 1

Там надо пропущенные цифры вствлять ?

Answer 2

4у + 10 > _ + 2 + (1 - у) + 24 = 49 - 3 + (3 - 2z) < _ 1 - 4z += 7×(6 - 5t) - 5 + < 1 - 41t = -0.5 + (8x + 9) - 0.9 > 4x - 3

It looks like the equation is incomplete, as there are missing numbers and symbols. It is not possible to solve this equation without knowing the missing values. If you provide the complete equation, I would be happy to help you solve it.