Question

Ширина прямоугольника 7 см а длина на 2 см больше найдите периметр и площадь прямоугольника

Answer 1

Решение:

1) 7 + 2 = 9 (см) -  длина прямоугольника
2) 2 * (7 + 9) = 32 (см) - периметр прямоугольника
3) 7 * 9 = 63 (см^2) - площадь прямоугольника

Ответ: периметр - 32 см, площадь - 63 см^2

Answer 2

Найдем длину прямоугольника
7+2=9 см
найдем его периметр
$P=2*(a+b)=2*(7+9)=2*16=32$ см
и его площадь
$S=a*b=7*9=63$ см²

Answer 3

Calculation of Perimeter and Area of a Rectangle

To find the perimeter and area of a rectangle, we need to know the width and length of the rectangle. In this case, the width of the rectangle is given as 7 cm, and the length is 2 cm more than the width.

Let's calculate the perimeter and area of the rectangle step by step.

Step 1: Calculate the Length of the Rectangle The length of the rectangle is given as 2 cm more than the width. Since the width is 7 cm, the length would be 7 cm + 2 cm = 9 cm.

Step 2: Calculate the Perimeter of the Rectangle The perimeter of a rectangle is given by the formula: P = 2 * (length + width).

Substituting the values, we have: P = 2 * (9 cm + 7 cm) = 2 * 16 cm = 32 cm.

Therefore, the perimeter of the rectangle is 32 cm.

Step 3: Calculate the Area of the Rectangle The area of a rectangle is given by the formula: A = length * width.

Substituting the values, we have: A = 9 cm * 7 cm = 63 cm^2.

Therefore, the area of the rectangle is 63 cm^2.

So, the perimeter of the rectangle is 32 cm and the area is 63 cm^2.