Question

Найти cosa и tga .если sina =5/13 и Пи /2< a <П

Answer 1

Если  П/2< a <П , то cosa<0 и tga<0

sina =5/13, cosα=-√1-25/169=-√144/169=-12/13

tgα=5/13:(-12/13)=-5/12

Answer 2

Finding the Values of `cosa` and `tga`

To find the values of `cosa` and `tga`, we need to use the given information that `sina = 5/13` and `π/2 < a < π`.

The trigonometric functions `sina`, `cosa`, and `tga` are related by the following identities:

- `sina = opposite/hypotenuse` - `cosa = adjacent/hypotenuse` - `tga = opposite/adjacent`

Since `sina = 5/13`, we can assume a right triangle with an opposite side of length 5 and a hypotenuse of length 13. Let's call the adjacent side `x`.

Using the Pythagorean theorem, we can find the value of `x`:

x^2 + 5^2 = 13^2
x^2 + 25 = 169
x^2 = 144
x = 12

Now that we know the value of `x`, we can find `cosa` and `tga`:

cosa = x/hypotenuse = 12/13
tga = opposite/adjacent = 5/12

Therefore, the values of `cosa` and `tga` are 12/13 and 5/12, respectively.

Please note that the search results provided by You.com did not contain the specific values of `cosa` and `tga` for the given conditions. The calculations above were done based on the given information and trigonometric identities.