Question

X^2+5x-14=0 Как решить?

Answer 1

Ax²+bx+c=0
несколькими способами
1. через дискриминант 
D=b²-4ac
x₁₂=(-b+-√D)/2a
X^2+5x-14=0 
D=5² - 4 * 1*(-14)=25+56=81=9²
x₁₂=(-5+-9)/2= -7  2
x₁=-7
x₂=2
2. обратная теорема Виета
x₁+x₂=-b/a=-5
x₁*x₂=c/a=-14
x₁=-7
x₂=2
3. Выделение полного квадрата
ну еще можно

Answer 2

$x^2+5x-14=0 D=56+25=81 \\X1=(-5-9)/2 =-7 \\X2=(-5+9 )/2=2$

Answer 3

Solving the Equation x^2 + 5x - 14 = 0

To solve the equation x^2 + 5x - 14 = 0, we can use the quadratic formula, which states that for an equation in the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

Let's calculate the solutions using this formula.

Applying the Quadratic Formula

For the equation x^2 + 5x - 14 = 0, we have: - a = 1 - b = 5 - c = -14

Using the quadratic formula: x = (-5 ± √(5^2 - 4*1*(-14))) / (2*1)

Calculating the Solutions

Now, let's calculate the solutions for x using the quadratic formula: x = (-5 ± √(25 + 56)) / 2 x = (-5 ± √81) / 2 x = (-5 ± 9) / 2

So, the solutions for x are: x = (-5 + 9) / 2 = 4 / 2 = 2 x = (-5 - 9) / 2 = -14 / 2 = -7

Therefore, the solutions for the equation x^2 + 5x - 14 = 0 are x = 2 and x = -7.

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