Question

из одного населенного пункта вышли в одном направлении два путника первый двигался со скоростью 70 метров минуту 2 двигался быстрее Через 10 минут опередил 1 на 600 метров с какой скоростью он двигался

Answer 1

Пусть второй путник двигался со скоростью х метров в минуту, тогда за 10 минут он прошел путь 10х
составим уравнение
10х - 70×10 = 600
10х - 700 = 600
10х = 600 + 700
10х = 1300
х = 1300 : 10
х = 130 (метров в минуту - скорость второго путника)

Answer 2

Problem Analysis

Two travelers started from a single settlement in the same direction. The first traveler moved at a speed of 70 meters per minute, while the second traveler moved faster. After 10 minutes, the second traveler overtook the first traveler by 600 meters. We need to find the speed at which the second traveler was moving.

Solution

Let's assume the speed of the second traveler is x meters per minute.

After 10 minutes, the first traveler would have covered a distance of 70 * 10 = 700 meters.

At this point, the second traveler overtakes the first traveler by 600 meters. Therefore, the distance covered by the second traveler in 10 minutes is 700 + 600 = 1300 meters.

To find the speed of the second traveler, we can set up the following equation:

x * 10 = 1300

Simplifying the equation, we get:

x = 1300 / 10 = 130 meters per minute.

Therefore, the second traveler was moving at a speed of 130 meters per minute.

Answer

The second traveler was moving at a speed of 130 meters per minute.