Question

4*(5-y)-30= -8*(9+x)+50= (-12)*(-a-2)-10= -19*(2-x)+20= 16*(7-a)-90= -15*(x+4)+60= 20+3(x-15)= 16-4(2+a)= -35-12(b-3)= -18+8(4-x)= 42-6(7+y)= 29-3(t-8)= Дайте пожалуйста ответы.

Answer 1

1)-10-4y
2)2-22-8x
3)12a+14
4)-18+19x
5)22-16a
6)-15x
7)-15+3x
8)8-4a
9)1-12b
10)14-8x
11)-6y
12)-3t+61

Answer 2

4*(5-y)-30 = -8*(9+x)+50 20-4y-30 = -72-8x+50 -4y-10 = -8x-22 -4y+8x = -12

(-12)*(-a-2)-10 = -19*(2-x)+20 12a+24-10 = -38+19x+20 12a+14 = 19x-18 12a-19x = -32

16*(7-a)-90 = -15*(x+4)+60 112-16a-90 = -15x-60 22-16a = -15x 16a-15x = 22

20+3(x-15) = 16-4(2+a) 20+3x-45 = 16-8-4a 3x-25 = 8-4a 3x+4a = 33

-35-12(b-3) = -18+8(4-x) -35-12b+36 = -18+32-8x -12b+13 = 14-8x -12b+8x = 1

42-6(7+y) = 29-3(t-8) 42-42-6y = 29-3t+24 -6y = 53-3t 6y = 3t-53

Now, you can solve the system of equations to find the values of y, x, a, b, and t. Let me know if you need further assistance!