Question

Троє рибалок впіймали 75 окунів і вирішили зварити юшку. Коли один рибалка дав 8 окунів, другий — 12, а третій — 7, то окунів у них залишилося порівну. Скільки окунів упіймав кожний?

Answer 1

1рибалка-16
2рибалка-28
3рибалка-31

Answer 2

Solution:

To solve this problem, we can use a system of equations to represent the given information and then solve for the number of fish each fisherman caught.

Let's denote the number of fish caught by the first fisherman as x, by the second fisherman as y, and by the third fisherman as z.

We are given the following information: 1. The total number of fish caught is 75: x + y + z = 75. 2. When the first fisherman gave 8 fish, the second fisherman gave 12 fish, and the third fisherman gave 7 fish, they had an equal number of fish left: x - 8 = y - 12 = z - 7.

We can use the second piece of information to express y and z in terms of x: - y = x - 4 - z = x + 1

Now, we can substitute these expressions into the first equation and solve for x.

Calculation:

Substituting the expressions for y and z into the first equation: x + (x - 4) + (x + 1) = 75 3x - 3 = 75 3x = 78 x = 26

Now that we have found the value of x, we can find the values of y and z using the expressions we derived earlier: y = x - 4 = 26 - 4 = 22 z = x + 1 = 26 + 1 = 27

Conclusion:

So, the first fisherman caught 26 fish, the second fisherman caught 22 fish, and the third fisherman caught 27 fish.