Question

Открыли 2 выставки картин в каждом зале этих выставок одинаково количество картин. На первой выставки 12 залов на второй 18 залов и на 120 картин больше чем на первой выставке сколько картин на каждой выставке? да я знаю модет и легко просто мне очень много задали буду очень благодарна всем кто мне поможет и решит эту задачу *(

Answer 1

Пусть х картин в 1 зале
Тогда х•12 картин на первой выставке
Значит х•18 картин на второй выставке
Известно , что на 2ой выставке на120 картин больше
Составим уравнение :
18•х-12•х=120
6х=120
Х=120:6
Х=20
1) 20•12= 240 картин на 1 выставке
2) 20•18=360 картин на 2 выставке

Answer 2

Problem Analysis

We are given two art exhibitions, each with a different number of halls. The number of paintings in each hall is the same for both exhibitions. We are also told that the second exhibition has 120 more paintings than the first exhibition. We need to determine the number of paintings in each exhibition.

Solution

Let's assume that the number of paintings in each hall is x.

For the first exhibition, which has 12 halls, the total number of paintings is given by: Total paintings in first exhibition = x * 12.

For the second exhibition, which has 18 halls, the total number of paintings is given by: Total paintings in second exhibition = x * 18.

We are also told that the second exhibition has 120 more paintings than the first exhibition. So, we can set up the following equation: Total paintings in second exhibition = Total paintings in first exhibition + 120.

Substituting the values from the previous equations, we get: x * 18 = x * 12 + 120.

Now, let's solve this equation to find the value of x.

Calculation

To solve the equation x * 18 = x * 12 + 120, we can simplify it as follows: 18x = 12x + 120.

Subtracting 12x from both sides of the equation, we get: 6x = 120.

Dividing both sides of the equation by 6, we get: x = 20.

Answer

Therefore, each exhibition has 20 paintings in each hall.