Question

Где будет ответ 12? 3 3/7 х 2 1/5 + 5 4/7 х 1 1/5 (три целые три седьмых • две целые одна пятая и тд) 6 4/7 х 1 1/5 - 3 3/7 х 1 1/5 3 3/7 х 1 1/5 + 6 4/7 х 1 1/5 Или такого нет И желательно везде ответы

Answer 1

1.  3 3/7*2 1/5=24/7*11/5=264/35
5 4/7*1 1/5=39/7*6/5=234/35
264/35+234/35=498/35=14 8/35
2.  6 4/7*1 1/5=46/7*6/5=276/35
     3 3/7*1 1/5=24/7*6/5=144/35
     276/35-144/35=132/35=3 27/35
3.   3 3/7*1 1/5=144/35
      6 4/7*1 1/5=276/35
      144/35+276/35=420/35=12

Answer 2

Solving the Equation

To solve the equation 12 3/7 x 2 1/5 + 5 4/7 x 1 1/5 - (3 3/7 x 1 1/5 + 3 3/7 x 1 1/5 + 6 4/7 x 1 1/5), we can follow these steps:

1. Calculate the products of the mixed numbers. 2. Subtract the sum of the products from the first step.

Step 1: Calculate the Products

First, we calculate the products of the mixed numbers: - 12 3/7 x 2 1/5: - The product of 12 3/7 and 2 1/5 is 26 6/35. - 5 4/7 x 1 1/5: - The product of 5 4/7 and 1 1/5 is 6 9/35. - 3 3/7 x 1 1/5: - The product of 3 3/7 and 1 1/5 is 4 2/35. - 6 4/7 x 1 1/5: - The product of 6 4/7 and 1 1/5 is 8 8/35.

Step 2: Subtract the Sum of the Products

Next, we subtract the sum of the products from the first step: - (26 6/35 + 6 9/35) - (4 2/35 + 8 8/35) - 32 15/35 - 12 10/35 - 20 5/35 - 20 1/7

Therefore, the solution to the equation 12 3/7 x 2 1/5 + 5 4/7 x 1 1/5 - (3 3/7 x 1 1/5 + 3 3/7 x 1 1/5 + 6 4/7 x 1 1/5) is 20 1/7.